.5x^2+3x-3.5=0

Solution for .5x^2+3x-3.5=0 equation:

.5x^2+3x-3.5=0

a = .5; b = 3; c = -3.5;
Δ = b2-4ac
Δ = 32-4·.5·(-3.5)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-4}{2*.5}=\frac{-7}{1}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+4}{2*.5}=\frac{1}{1}
=1
$